find the quadratic polynomial having alpha and beta as it zeroes when Alpha + beta =24 and alpha - beta =8
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Answered by
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Hey !!!
@+€ = 24-----1)
@-€ = 8------2
for finding alpha and bita as roots of this equation we can substracting or add then we get @ and €
so we adding here
@ + € = 24
@ -€ = 8
--------------
2@ = 32
@ = 16
now putting the value of. @ on equation 1 then we get €
@ + € = 24
16 + € = 24
€ = 24 - 16= 8
now , as you know that a quadratic equation is in the form of
ax² + bx+c
@ = 15
€ = 9
@+€ = -b/a = -24 ------3)
@ ×€ = 128= c/a-----------4)
ax² - (@+€)x + @€
ax² - (24) + 128 [from 3 and 4 equation ]
here a = 1 so ,
the quadratic form is
(x² - 24x + 128) Answer
***********************************
Hope it helps you !!!
@Rajukumar111
@+€ = 24-----1)
@-€ = 8------2
for finding alpha and bita as roots of this equation we can substracting or add then we get @ and €
so we adding here
@ + € = 24
@ -€ = 8
--------------
2@ = 32
@ = 16
now putting the value of. @ on equation 1 then we get €
@ + € = 24
16 + € = 24
€ = 24 - 16= 8
now , as you know that a quadratic equation is in the form of
ax² + bx+c
@ = 15
€ = 9
@+€ = -b/a = -24 ------3)
@ ×€ = 128= c/a-----------4)
ax² - (@+€)x + @€
ax² - (24) + 128 [from 3 and 4 equation ]
here a = 1 so ,
the quadratic form is
(x² - 24x + 128) Answer
***********************************
Hope it helps you !!!
@Rajukumar111
vishnurajD:
thanks a lot
Answered by
2
hope this helps u ..........plz reply if it is correct
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