Question

Find the quadratic polynomial having zeroes as -3 and 2

Answer 1

Hey friend, ☺️ here is your answer _____________________________

Let alpha and beta be the two zeroes of the polynomial.
Therefore, alpha = - 3 and beta = 2

Sum of zeroes = alpha + beta = - 3 + 2 = - 1
Product of zeroes = alpha*beta = - 3*2 = - 6

The required polynomial is :-
p(x) = k[x^2 - (Sum of zeroes) + (product of zeroes)]
p(x) = k[x^2 - (-1) + (-6)]
p(x) = k( x^2 + 1 - 6)

Put k= 1
p(x) = x^2 + 1 - 6

HOPE IT HELPS YOU....