find the quadratic polynomial if the sum and product of the zeros are given as root 2 and minus 3 / 2 respectively
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this can be helpful to you....
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paramvachhani:
your method is too short buddy
thia is only one mark question so we can answer it directly
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We know that every quadratic equation is based on this relation..
p(x) = kx² - (α+β)x + αβ where, α and β are the zeroes of given polynomial.
Now putting values of (α+β)and αβ in above equation, we get ...
p (x) = x² - (√2)x + (-3/2) = 0x² - √2x - 3/2 = 0
Let us multiply both sides by 2, we get...
2x² - 2√2x -3 = 0
Hence, the required polynomial is 2x² - 2√2x -3.
Hope you got it......
p(x) = kx² - (α+β)x + αβ where, α and β are the zeroes of given polynomial.
Now putting values of (α+β)and αβ in above equation, we get ...
p (x) = x² - (√2)x + (-3/2) = 0x² - √2x - 3/2 = 0
Let us multiply both sides by 2, we get...
2x² - 2√2x -3 = 0
Hence, the required polynomial is 2x² - 2√2x -3.
Hope you got it......
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