Find the quadratic polynomial if the zeroes of it are 2,-1/3
Answers
Answered by
6
Answer:
Heya !!
Let Alpha = 2 and Beta = -1/3.
Sum of zeroes = 2 - 1/3 = 6 - 1/3 = 5/3
And,
Product of zeroes = 2 × -1/3 = -2/3.
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes) X + Product of zeroes.
=> X² - (5/3)X + (-2/3)
=> X² - 5X/3 - 2/3
=> 3X² - 5X - 2.
Answered by
7
Answer:
heya mate there's your answer
The general form of quadratic equation is,
x^2-(sum of roots)x +(product of roots)=0
given roots are 2,-1/3
then equation is,
x^2-(2+(-1/3))x +(2(-1/3))=0
x^2-(2-1/3)x+(-2/3)=0
x^2-(6-1/3)x+(-2/3)=0
x^2-(5/3)x+(-2/3)=0
3x^2-5x-2=0×3
3x^2 -5x -2=0
hope it helps you
Thank you
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