Math, asked by adirockstar596, 1 year ago

Find the quadratic polynomial if the zeroes of it are 2,-1/3

Answers

Answered by ronak960
6

Answer:

Heya !!

Let Alpha = 2 and Beta = -1/3.

Sum of zeroes = 2 - 1/3 = 6 - 1/3 = 5/3

And,

Product of zeroes = 2 × -1/3 = -2/3.

Therefore,

Required quadratic polynomial = X²-(Sum of zeroes) X + Product of zeroes.

=> X² - (5/3)X + (-2/3)

=> X² - 5X/3 - 2/3

=> 3X² - 5X - 2.

Answered by manasa1010
7

Answer:

heya mate there's your answer

The general form of quadratic equation is,

x^2-(sum of roots)x +(product of roots)=0

given roots are 2,-1/3

then equation is,

x^2-(2+(-1/3))x +(2(-1/3))=0

x^2-(2-1/3)x+(-2/3)=0

x^2-(6-1/3)x+(-2/3)=0

x^2-(5/3)x+(-2/3)=0

3x^2-5x-2=0×3

3x^2 -5x -2=0

hope it helps you

Thank you

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