Question

Find the Quadratic polynomial if the zeroes of it are 2 and 3

1  respec-

tively​

Answer 1

Answer:

${x}^{2} - ( 2 )x + ( 3 )$

Step-by-step explanation:

$Let, \: \alpha \: and \: \beta \: be \: the \: zeroes \: of \: the \: quadratic \: polynomial$

$\color{red} \huge{Given: - }$

$\alpha + \beta = 2 \: \: \: and \: \: \: \alpha \times \beta = 3$

$We \: know \: t hat,$

${x}^{2} - ( \alpha + \beta )x + ( \alpha \times \beta )$

${x}^{2} - ( 2 )x + ( 3 )$

$Hence,{x}^{2} - ( 2 )x + ( 3 ) \: is \: the \: required \: quadratic \: equation$