Question

find the quadratic polynomial in 10/3,1 with the given number as the sum and product of it's zero respectively​

Answer 1

Answer:

x²-(Sum of roots)x + (Product of roots) = 0

x²-(10/3+1)x + (10/3 x1 ) = 0

x²-((10+3)/3)x + (10/3 ) = 0

3x²-13x + 10 = 0 x3 =0

3x²-13x + 10 =0

Step-by-step explanation:

Answer 2

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