Math, asked by neeraj10110, 9 months ago

Find the quadratic polynomial in each case, with the given numbers as the sum and
product of its zeroes respectively.
(iii) 0, 75
(1) 1 -1
(iv) 1,1
(5) J2, 1/3
(+)-1
(vi) 4, I​

Answers

Answered by EuphoricEpitome
3

Answer:

1. x-y+75= 0

product of zeroes = 0×75= 0

2.x-y-2= 0

product of zeroes= 1×-1= -1

3. (x/6) -y+0= 0

product of zeroes= 2×1/3= 2/3

4. x -4y+0= 0

product of zeroes= 4×1= 4.

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