find the quadratic polynomial in each case with the given number as the sum and product of its zeroes respectively 0,^5
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Answer:
Sum of zeroes (α+β)=0
Product of the zeroes =αβ=
5
ax
2
+bx+c is
k[x
2
−(α+β)x+αβ],
where k is a constant and k
=0, then
k[x
2
−(0)x+(
5
)]
⇒x
2
+
5
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