Question

Find the quadratic polynomial of the zeroes root 2+1
Urgent plzz

Answer 1

Answer:

hence foundddd

Step-by-step explanation:

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Answer 2

Here, one zero is $\mathtt{(\sqrt{2}+1)}$

Then the other zero be $\mathtt{(\sqrt{2}-1)}$

Thus the required polynomial be

$\quad\mathtt{=\{x-(\sqrt{2}+1)\}\:\{x-(\sqrt{2}-1)\}}$

$\quad\mathtt{=\{(x-\sqrt{2})-1\}\:\{(x-\sqrt{2})+1\}}$

$\quad\mathtt{=(x-\sqrt{2})^{2}-1^{2}}$

$\quad\mathtt{=x^{2}-2\sqrt{2}+2-1}$

$\quad\mathtt{=x^{2}-2\sqrt{2}+1}$