Question

Find the quadratic polynomial of whose zeroes are 2,-1

Answer 1

Answer:

The Quadratic Polynomial is (x-2)(x+1)=x^2-2x+x-2x^2-x-2=0.

This is your answer :)

Answer 2

Answer:

The quadratic enquation is F(x) = X^(2) - x - 2

As the zeroes of the polynomial is 2,-1

•X=2, then X - 2 = 0

•X=-1, then X + 1 = 0

Of these two are the zeroes of the Polynomial as they are making the remainder zero and If the remainder is zero then the X - 2 and X +1 are the factor of F (x) .

F (x) = (X - 2) (X + 1)

(using (X-a) (X-b) = x^(2)+(a+b)x+ab)

F (x) = X^(2) + (-2+1)X + (-2)(1)

F (x) = X^(2) - x - 2

As you can check this by applying F (2) and F (-1)