Find the quadratic polynomial such that sum of its zeros is 9 and difference between zeros is 7
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Answered by
17
Answer:
x^2 - 9x + 8
Step-by-step explanation:
Let the zeroes be a and b.
a + b = 9
a - b = 7
(a +b)^2 - (a - b)^2 = 81 - 49
4ab = 32
ab = 8
quadratic equation = x^2 - (sum of zeroes)x + (product of zeroes)
=> x^2 - 9x + 8
Answered by
8
Answer:
so this is the another way to get your answer
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