Find the quadratic polynomial such that sum of its zeros is 10 and different between the zeroes is 9.
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Answer:
every quadratic equations has 2 zeros (in other words roots)
Step-by-step explanation:
let a,b be the zeros(roots) of given Quadratic polynomial
given:
a+b = 10 (sum=10) --------(1)
a-b = 9 (difference=9) ------(2)
solving (1) and (2)
a=19/2
b= 1/2
generally the quadratic polynomial = (x-a)(x-b)
=(x-19/2)(x-1/2)
=x^2 -10x +19/4
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