Question

find the quadratic polynomial sum and product of whose zero are -3 and 6 ​

Answer 1

Given :

»› Sum of zeroes = -3

»› Product of zeroes = 6

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$\large \star \: \: \: \: \bf \underline \red{Required \: Answer :}$

$\: \: \: \: \: \leadsto \text{ Let the zeroes be} \: \: \alpha \: \text{ and} \: \: \beta$

$» \: \text{ Sum \: of \: zeroes = - \: 3}$

$\implies \alpha + \beta = - 3$

$\: » \text{ Product \: of \: zeroes = 6 }$

$\implies \alpha \: \times \beta = 6$

Now we know that, p(x) =

$\large \boxed { = {x}^{2} - ( \alpha + \beta )x + \alpha \beta }$

$\large{ = {x}^{2} - ( - 3)x + 6 }\\ \large{=k ({x}^{2} + 3x + 6 )}$

$\: \: \: \: \: \: \: \: \: \: where \: \red k \: is \: any \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: real \: number \:$

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$\bf \large \underline \red { Answer : }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large{=k ({x}^{2} + 3x + 6 )}$

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hope it helps....

Answer 2

Answer:

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