Find the quadratic polynomial , sum of whose zeroes is 2 and product is -8. hence find the zeroes of the polynomial
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Answered by
3
x^2 -2x+8 is the polynomial. And the zeroes are 4,-2.
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15
sum of zeroes=2
product of zeroes=-8
p(x)=x^2-(sum)x+product
=x^2-2x-8
we will do middle splitting.
x^2-2x-8=0
x^2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
x=4,-2
product of zeroes=-8
p(x)=x^2-(sum)x+product
=x^2-2x-8
we will do middle splitting.
x^2-2x-8=0
x^2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
x=4,-2
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