find the quadratic polynomial sum of whose zeroes is 8 and their product is 12 hence find the zeros of the polynomial
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HEY , MATE ....?!!!!!!!
HERE IS YR . SOLUTION ...
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HERE IS YR . SOLUTION ...
HOPE IT WILL HELP YOU ... .:-)
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pandu9612:
tnq soo much
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hello mate!!
let the quadratic equation be ax^2+bx+c
so, sum of zeroes=-b/a
=8
product of zeroes=c/a
=12
let a=1, then b=-8 and c=12
so, quadratic equation is x^2-8x+12
now, x^2-8x+12=0
x^2-6x-2x+12=0
x(x-6)-2(x-6)=0
(x-2)(x-6)=0
x-2=0. x-6=0
x=2. x=6
so, the zeroes are 2 and 6
hope it helps!!
let the quadratic equation be ax^2+bx+c
so, sum of zeroes=-b/a
=8
product of zeroes=c/a
=12
let a=1, then b=-8 and c=12
so, quadratic equation is x^2-8x+12
now, x^2-8x+12=0
x^2-6x-2x+12=0
x(x-6)-2(x-6)=0
(x-2)(x-6)=0
x-2=0. x-6=0
x=2. x=6
so, the zeroes are 2 and 6
hope it helps!!
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