Math, asked by pandu9612, 1 year ago

find the quadratic polynomial sum of whose zeroes is 8 and their product is 12 hence find the zeros of the polynomial

Answers

Answered by Anonymous
22
HEY , MATE ....?!!!!!!!

HERE IS YR . SOLUTION ...

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Answered by dishagaur748
3
hello mate!!


let the quadratic equation be ax^2+bx+c

so, sum of zeroes=-b/a
=8

product of zeroes=c/a
=12

let a=1, then b=-8 and c=12

so, quadratic equation is x^2-8x+12

now, x^2-8x+12=0
x^2-6x-2x+12=0
x(x-6)-2(x-6)=0
(x-2)(x-6)=0
x-2=0. x-6=0
x=2. x=6


so, the zeroes are 2 and 6

hope it helps!!
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