Question

Find the quadratic polynomial, sum of whose zeros is 8 and their product is 12. Hence find the zeros of the polynomial.

Answer 1

=k(x²-(α+β)x+αβ)
=k(x²-8x+12)
here k=1
=x²-8x+12
=x²-2x-6x+12
=x(x-2)-6(x-2)
=(x-2)(x-6)
⇒x-2=0                                    or                             ⇒x-6=0
⇒x=2                                        or                            ⇒x=6

Answer 2

Answer:

x²–8x–12

Step-by-step explanation:

= k(x²-(a+ẞ)x+aẞ)

= k(x²-8x+12) here k=1

= x²-8x+12

= x²-2x-6x+12

= x(x-2)-6(x-2)

= (x-2)(x-6)

⇒ x-2=0 or ⇒ x-6=0

⇒ x=2 or ⇒ x=6