Question

find the quadratic polynomial ,the sum &product of whose zeroes are -8 and 12 respectively find the zeroes​

Answer 1

sum of roots =

= -b/a = 1/1

\alpha +\beta

product of roots =

\alpha \beta

= c/a = -12/1

Step-by-step explanation:

so, from the above data we get to know that a = 1

now b = -1     (as in above equation -b = 1  .... so b = -1)

c=-12

lets substitute the vales in the general quadratic equation form which is,

ax^{2} + bx + c = 0

which is,

x^{2} - x - 12

(option a)

thus this is the required quadratic equation,

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Answer 2

Answer:

Given: Sum of zeroes =−12 and product of zeroes =1

We know,

p(x)=x2−(sum of zeroes)x+(product of zeroes)

⇒p(x)=x2−(−12)x+1

⇒p(x)=x2+12x+1

is the required polynomial.