Question

Find the quadratic polynomial,the sum and product of whose zeros are√2 and -3/2

Answer 1

Answer:

2x2 - 2root2x - 3

Step-by-step explanation

zeroes are given root 2 and -3/2

sum is root 2

product is -3/2

k( x2 -(sum)x + product)

k(x2 -(root2)x -3/2)

to remove the denominator,

2(x2 -root2x -3/2)

therefore, the equation is 2x2 - 2root2x -3

Answer 2

Answer:

2x2 - 2root2x - 3

Step-by-step explanation:

Zeroes are given root 2 and -3/2

Sum is root 2

Product is -3/2

k( x2 -(sum)x + product

k(x2 -(root2) x -3/2)

k(x2 - sumx + product)

k(x2 -(root2) + -3/2)

to remove the denominator ,

2(x2 -root2x -3/2)

therefore, the equation is 2x2 - 2root2x

-3