Question

find the quadratic polynomial the sum and product of whose zero are -11,9 respectively​

Answer 1

✨YOUR ANSWER✨

Sum of zeros =6, product of zeros=9

Quadratic polynomial= x²-(sum of zeroes)x+ product of zeroes

Therefore Quadratic polynomial is x²-6x+9

Also x²+6x+9=0

or, (x-3)(x-3)=0

Therefore x=3,3

Hence zeroes are 3,3

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Answer 2

$\huge\red{\boxed{Answer}}$

$α + β= ( - 11) \\α β = 9 \: \: \: \:$

$\large{\boxed{\boxed{p(x) = {x}^{2} - (sum \: of \: the \: zeroes)x + (product \: of \: the \: zeroes) }}}$

$p(x) = {x}^{2} - (α + β)x + αβ$

$p(x) = {x}^{2} - ( - 11)x + (9)$

$p(x) = {x}^{2} + 11x + 9$

$∴ \: \: the \: quadratic \: polynomial \: the \: sum \: and \: product \: of \: whose \: zeroes \: are \: - 11 \: , \: \: 9 \: \: respectively \: :$

$\large{\boxed{p(x) = {x}^{2} + 11x + 9}}$

$Hope \: \: this \: \: helps \: \: you \: !$