Question

find the quadratic polynomial,the sum and product of whose zeroes are root of 2 and 1/3 respectively. Also find its zeroes

Answer 1

↑ Here is your answer ↓
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Sum = $\sqrt{2}$, Product = $\frac{1}{3}$

General form of a quadratic equation => $x^2 - (a + B)x + aB$

Note: a & B are zeroes of the polynomial.

So the polynomial is $x ^2 - \sqrt 2x + 1/3$

It can be re-written as: $3x^2 - 3 \sqrt 2x + 1$

 Now we should fine the zeroes!

$3x^2 - 3 \sqrt 2x + 1$

By using quadratic formula, we get

$\frac{1}{\sqrt2} +_- \frac {1}{\sqrt 6}$

Answer 2

Step-by-step explanation:

3 x square - 3√2 X + 1

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