Find the quadratic polynomial the sum and product of whose zeroes are -3 and 2 respectively
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Answered by
2
Let the zeroes be a and b
a + b = -3
ab = 2
Required polynomial = k { }, where k is any constant
= k { }
= k { }
Hope this helps you
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Answered by
1
Let a and b be the roots.
Sum, a+b= -3
Product, ab= 2
So the polynomial is
x^2 - (a+b)x + ab
—->
x^2+3x+2
Sum, a+b= -3
Product, ab= 2
So the polynomial is
x^2 - (a+b)x + ab
—->
x^2+3x+2
shameemamk:
x^2+3x+2=(x+1)(x+2). So the roots are -1 and -2. Sum of the roots= -1+-2=-3. Product of the roots = -1x-2=2
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