Question

find the quadratic polynomial , the sum and product of zeroes is ax-3 and 2,respectively​

Answer 1

Answer:

(1-a)x²+3x+2

Step-by-step explanation:

Given that,

sum of the zeroes of the polynomial is = ax-3

product of the zeroes of the polynomial is = 2

let the zeroes of the polynomial be α & β

as we know that,

α+β = -b/a

⇒ax-3 = -b/a→(1)                              (∵Given)

α.β = c/a

⇒2 = c/a→(2)                                     (∵given)

the general form of quadratic equation is k(x²-(α+β)x+α.β)

(∵Where k is any constant)

⇒k(x²-(ax-3)x+2)

⇒k(x²-(ax²-3x)+2)

⇒k(x²-ax²+3x+2)

⇒k((1-a)x²+3x+2)

let, k=1

⇒1((1-a)x²+3x+2)

⇒(1-a)x²+3x+2

∴the quadratic polynomial is (1-a)x²+3x+2.

HOPE THIS WOULD BE HELPFUL FOR YOU