Question

Find the quadratic polynomial,the sum and product of zeroes are √2 & -3/2 respectively. Find the zeroes

Answer 1

here,
a+b= √2
a×b= -3/2

formula will be
= x^2 - (sum of root)x + (product of root)
= x^2 - (√2)x + (-3/2)
multiply the denominator 2 with all excepr 3 numerrator....

= 2x^2 - 2√2x -3...

Answer 2

sum of zeroes are √2
product of zeroes are -√3/2
so quadratic polynomial is 2x2 + 2√2 + 3 =0
2x2 + 3√2x + √2x + 3 =0
√2x (√2x+3) + 1 (√2+3) =0
(√2x+ 3 ) (√2x+3)=0
x=-3/√2 or x=-3/√2