Question

find the quadratic polynomial the sum and the product of the zeros are
$\sqrt{3} \: and \: - \sqrt{3}$
​

Answer 1

Step-by-step explanation:

$\alpha + \beta = \sqrt{3} \\ \alpha \beta = - \sqrt{3} \\ requird \: quadratic \: polynomial \\ {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ {x}^{2} - ( \sqrt{3} )x + ( - \sqrt{3)} \\ {x}^{2} - \sqrt{3} x - \sqrt{3}$