Question

Find the quadratic polynomial the sum of the product whose zeroes are - 5 and 3 respectively

Answer 1

Given

$\bold{ Sum \ of \ zeroes} = -5$

$\bold{ Product \ of \ zeroes} = 3$

SOMETHING YOU NEED TO KNOW

$\boxed{\bold{Required \ quadratic \ polynomial}}\\ = x^{2} -(Sum \ of \ zeroes ) x + Product \ of \ zeroes}}$

Therefore, the required quadratic equation is

$x^{2} -(-5)x + 3 = 0\\\boxed{\boxed{\bold{x^{2} + 5x + 3 = 0}}}}$

                                                       

Answer 2

GIVEN :

Sum of the polynomial = ( -5 )

Product of the polynomial = 3

TO FIND :

Quadratic polynomial

SOLUTION :

The formula / layout for quadratic polynomial is -

${\small{x}^{2} \:-\: (Sum\:of\: the \:zeroes)x \: + \: Product\: of \:the\: zeroes }$

Therefore the quadratic polynomial becomes -

$\sf {x}^{2} \:-\: (-5)x \: + \: 3$

$\sf {x}^{2} \:+\: 5x \: + \: 3$