Question

Find the quadratic polynomial the sum of where zeros is-10 and product of its zero is -39​

Answer 1

Step-by-step explanation:

Let S be the sum of the roots and P be the product of the roots for any polynomial ax^2+ bx + c.

Then,

Polynomial = x^2 + (S)x + (P)

= x^2 + (0)x + (-1)

= x^2 -1

roots = x^2 - 1 = 0

= (x+1)(x-1) = 0

x = +1 , -1

Plz mark it as the BRAINLIEST.

Answer 2

Answer:

x^2 - 49x + 390 = 0

Step-by-step explanation:

Let,

alpha = -10

beta = - 39

alpha + beta = - 10 - 39 = - 49

alpha beta = ( - 10 ) x - 39 = 390

x^2 - ( alpha + beta ) x + ( alpha beta ) = 0

x^2 - ( 49 ) x + 390 = 0

x^2 - 49x + 390 = 0