Question

fInd the quadratic polynomial the sum of whose zeroes is -10 and product of its zeroes is -39

Answer 1

Answer:

x² + 10x - 39

Step-by-step explanation:

The quadratic equation will be of form x² - (Sum of roots)x + Product of roots.

Sum of roots = -10

product of roots = -39

So Quadratic polynomial is

x² - (-10)x + (-39)

= x² + 10x - 39

Answer 2

Step-by-step explanation:

Solution:-

given

$\implies{ \boxed{ \red{ \alpha + \beta = - 10}}} \\ \implies{ \boxed{ \red{ \alpha \times \beta = - 39}}}$

general form of quadratic polynomial

$\implies{ \boxed{ \blue{ {x}^{2} - ( \alpha + \beta )x + \alpha \times \beta }}}$

now multiply constant k in equation we have find

$\implies{ \boxed{ \green{k( {x}^{2} - ( - 10)x + ( - 39))</strong><strong>=</strong><strong>0</strong><strong> }}} \\ \implies{ \boxed{ \green{k( {x}^{2} + 10x - 39)</strong><strong>=</strong><strong>0</strong><strong> }}}$

Answer:-

$k( {x}^{2} + 10x - 39)</u></strong><strong><u>=</u></strong><strong><u>0</u></strong><strong><u>$