Question

Find the quadratic polynomial, the sum of whose zeroes is 8 and their product is 12.Hence find the zeroes of the polynomial.​

Answer 1

Answer:

           $x^{2}-8Y+12=0$

Step-by-step explanation:

SUM OF ZEROES =   -B/A

               8/1          =   -B/A

                  -8   =   B

                  1     =   A

 PRODUCT OF ZEROES =  C/A

               12/1                     =     C/A

                12      =     C

                  1      =    A