Question

Find the quadratic polynomial, the sum of whose zeroes is 8 and their product is 12. Hence, find the zeroes of the polynomial. (cbse 2008)

Answer 1

$x {}^{2} - 8x + 12 = 0 \\ \\ \\ \\x(x - 6) - 2(x - 6) \\ (x - 2)(x - 6) = 0 \\ x - 2 = 0 \: or \: x - 6 = 0 \\ x = 2 \: and \: x = 6$