Question

find the quadratic polynomial the sum of whose zeros negative 5 and their product is 6

Answer 1

Heya !!




Sum of zeroes = -5



And,

Product of zeroes = 6





Therefore,


Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes.



=> X² - (-5)X + 6



=> X² + 5X + 6

Answer 2

$\textbf{Solution:}$

$let \: \alpha + \beta = - 5$

$\alpha \beta = 6$

Required polynomial
$= x {}^{2} - ( \alpha + \beta )x + \alpha \beta$

$= x {}^{2} - ( - 5)x + 6 \\ \\ = x {}^{2} + 5x + 6$

$\textbf{So, the required polynomial is:}$

$\boxed{x{}^{2} + 5x + 6 }$

$\textbf{Hope it will helps you}$