Question

Find the quadratic polynomial, the sum of whose zeros is √2 and their product is 1/3

Answer 1

By a formula we know that,

p(x) = K[x²-(a+b)x +ab]

p(x) = 3[x²-(√2)x + 1/3]

p(x) = 3[3x²-3√2x+1]/3

p(x) = 3x² - 3√2x +1