find the quadratic polynomial,the sum of whose zeros is 5/2 and their product is 1. hence find the zeros of the polynomial
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given sum of the zeroes= -b/a =>5/2
product of the zeroes =c/a => -1/1
but as the polynomial is x^2-(sum of zeroes)x +product of zeroes
the required polynomial will be 2x2 -5x - 2
product of the zeroes =c/a => -1/1
but as the polynomial is x^2-(sum of zeroes)x +product of zeroes
the required polynomial will be 2x2 -5x - 2
priisha:
but in place of -2 there should be 1, no?
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the standard form of an equation is
where s is sum of zeroes and p is the product
equatis is
if we take the LCM then equation will be
where s is sum of zeroes and p is the product
equatis is
if we take the LCM then equation will be
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