Question

find the quadratic polynomial the sum of whose zeros is 8 and their product is 12 hence find the zero of the polynomial​

Answer 1

Answer:

2,6

Step-by-step explanation:

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Answer 2

Answer:

$\alpha + \beta = 8 \\ \alpha \beta = 12 \\ x {}^{2} - ( \alpha + \beta )x + \alpha \beta \\ x {}^{2} - 8x + 12 \\ x {}^{2} - 6x - 2x + 12 \\ x(x - 6) - 2(x - 6) \\ (x - 2)( x - 6) \\ x = 2 \: \: \: \: x = 6$