Question

find the quadratic polynomial the sum of whose zeros is 8 and their products is -1 hence find the zeros of the polynomial.​

Answer 1

Answer:

Given:

$\alpha + \beta = 8$

&

$\alpha \beta = - 1$

•°•the structure of quadratic polynomial Is

${x}^{2} - (\alpha + \beta )x + \alpha \beta$

hence, the polynomial is

${x}^{2} - (8)x + (- 1)$

${x}^{2} - 8x - 1$

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