Question

find the quadratic polynomial the sum of whose zeros is root 2 and their product is minus 12 and find the zeros of the polynomial

Answer 1

Let us assume that the roots are a & b

According to the question,

a+b = √2....................(i)

& a*b = (-12)...................(ii)

Any quadratic polynomial is of form:-

x² - (a+b)x + (a*b).....................(iii)

Therefore, replacing values from equation (i) & (ii) into (iii)

So, the required polynomial is:-

x² - √2*x + (-12)

=> x² - x√2 -12

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Answer 2

Answer:

Step-by-step explanation:

The sum of two zeroes = 2√3 and product of two zeroes = 2

The quadratic equation is

x2 - (sum of two zeros)x + product of zeroes

x2 - 2√3 x + 2