Question

find the quadratic polynomial those zeroes are -2 and 1/3​

Answer 1

Answer:

$let \: \alpha = - 2 \: and \: \beta \: \: = \frac{ 1}{3} \\ soz = \frac{1}{3} - 2 = \frac{ - 5}{3} \\ poz = \frac{1}{3} \times - 2 = \frac{ - 2}{3} \\ \: quadratic \: eq {}^{n} = {x}^{2} + \frac{5x}{3} - \frac{2}{ 3} = 0 \\ 3 {x}^{2} + 5x - 2 \: is \: the \: \: required \: \: quadratic \: \: eq$

Answer 2

Step-by-step explanation:

Use the formula

p(x)=x²-(a+b)x-ab

where a+b is sum of zeros and ab is. product of zeros

p(x)=x²+5x/3-2/3

=3x²+5x-2

Hope u understand

Follow me...