find the quadratic polynomial where sum and product of zeroes are 1a and 1/a
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Answer:
ax^2-xa^2+1
Step-by-step explanation:
Formula-
x^2- (α+β)x + αβ
Given-
(α+β)=1a
αβ= 1/a
Substituting the values-
Then, x^2-x(a)+1/a
= a[(ax^2-xa^2+1)/a] {First take LCM and then multiply by a to cancle the denominator a}
=ax^2-xa^2+1
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