find the quadratic polynomial whose 1 of the zeroes is root 3 by 4 and product of the zeroes is -1 by 2
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Answer:
P(x) = 4√3x² + 5 - 2√3
Step-by-step explanation:
One zero of P(x) = √3 / 4
Let the other zero be a
Product of zeroes = -1 / 2
⇒ √3x / 4 = -1 / 2
⇒ √3x / 2 = -1
⇒ x = -2 / √3
P(x) = k ( x² - (α + β) + αβ)
= k ( x² - ( √3/4 - 2/√3 ) - 1/2 )
= k ( x² - ( -5 / 4√3 ) - 1/2 )
= k ( x² + 5 / 4√3 - 1/2 )
= If k = 4√3 then
P(x) = 4√3x² + 5 - 2√3
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