Find the quadratic polynomial whose are 1 and -3
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The zeroes are 1 and - 3.
Sum = 1 - 3 = - 2.
Product = 1*-3 = - 3.
Required polynomial = k{x² - (sum) x + product}, where k≠0.
= k{x²+2x-3}, where k≠0.
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Question
* Find the quadratic polynomial whose zeroes are 1 and -3
Solution
Method 1
Let the roots be α and β respectively
Given: α = 1 ; β = -3
We know that
Sum of the zeroes
=> α + β
=> 1 + (-3)
=> -2
Product of the zeroes
=> α × β
=> 1 × (-3)
=> -3
So, the polynomial = x² - (α + β) x + αβ = 0
=> x² - (-2) x + (-3) = 0
=> x² + 2x - 3 = 0
Method 2
Given:
x = 1 and x = -3 {roots of the equation}
=> (x - 1) (x + 3) = 0
=> x² + 3x - x - 3 = 0
=> x² + 2x - 3 = 0
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