Question

Find the quadratic polynomial whose product and
sum of zeroes are -13/5 and 3/5 respectively.​

Answer 1

Answer:

The sum of the zeroes α + β = 3/5 and product of zeroes αβ = -13/5

The quadratic equation will be

$x^2-(\alpha +\beta )x+\alpha \beta=0$

Therefore the equation is

$x^2-(\frac{3}{5} )x+(\frac{-13}{5}) =0$

Now dividing the equation with 5 we get,

$5x^2-3x-13=0$ is the equation.