Question

Find the quadratic polynomial whose roots are 2a &3b.

Answer 1

Sum of roots =2a+3b =2a+3b
Product of roots=2a×3b=6(a+b)
Now the quadratic equation will be
X^2 +2a+3b +6(a+b)

Answer 2

zeroes are given 2a and 3b .

for finding quadratic equation we use a formula

x2 + ( sum of zeroes ) x + product of zeroes .

so first of all Find sum and product of zero .

Therefore , sum of zero = 2a + 3b

and , product of zero = 2a × 3b = 6 ab .
.
now put the above formula

x2 + ( 2a + 3b )x + 6ab . is a required polynomial .
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