find the quadratic polynomial whose roots are 3+ root3 and 3- root3
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Step-by-step explanation:
Given :-
3+ root3 and 3- rroot3
To find :-
Find the quadratic polynomial whose roots are
3+ √3 and 3- √3 ?
Solution:-
Given roots are 3+ √3 and 3- √3
Let α = 3+√3
Let β = 3-√3
α + β = 3+√3+3-√3 = 3+3 = 6
α β = (3+√3)(3-√3)
It is in the form of (a+b)(a-b)
Where a = 3 and b =√3
(a+b)(a-b)=a^2-b^2
(3+√3)(3-√3) = 3^2-(√3)^2
=> 9-3
=> 6
We know that
If α and β are the roots ,then the Quadratic equation is x^2-(α +β)x+αβ = 0
=> x^2-(6)x+6 = 0
=> x^2-6x+6 = 0
Answer:-
The required quardratic equation is x^2-6x+6 = 0
Used formulae:-
- If α and β are the roots ,then the Quadratic equation is x^2-(α +β)x+αβ = 0
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