Question

find the quadratic polynomial whose sum and product of zeroes are 9 and 1/9

Answer 1

Heya!!! User!!! ✌

✔ Here's your answer friend,

==>

Given : Sum of the zeroes of polynomial 9

and,

the product of zeroes of polynomial is 1/9

Therefore,

➡ The required quadratic polynomial is

==> x² - (sum of the zeroes)x + (product of zeroes)

==> x² - (9)x + (1/9)

==> x² - 9x + 1/9

==> 9x² - 81x + 1 .........[ by multiplying whole equation by 9]

HOPE YOU GOT YOUR ANSWER :)

#BEBRAINLY
#TOGETHER WE GO FAR
#☺☺☺

Answer 2

Let the alpha, beta be the zero.

A/q

$\alpha + \beta = 9 \\ \\ \alpha \times \beta = 1 \div 9$
Write in the equation form

p(x)= k [x^2+(alpha+beta)x - (alpha×beta)]

p(x)= k [x^2+ 9x-1/9]

p (x)= k [9x^2+81x-1]

(where k is constant)

One of the polynomial is

9x^2 + 81x - 1. =>Answer

Hope it will helps you:-)