Question

find the quadratic polynomial whose sum and product of its zero are -8/3 and 4/3​

Answer 1

Answer:

Let the sum and product of zeroes be -8/3 and 4/3

so, The required polynomial :

x2- (sum of the zeroes)x + product of zeroes

x2 + 8/3x + 4/3

Answer 2

Answer :

• 3x²+8x+4

Given :

• Sum of zeroes      = -8/3
• Product of zeroes = 4/3

To find :

• Quadratic polynomial

Solution :

The quadratic equation will be in the form of :

⇒ x² - (sum of zeroes)x + (product of zeroes) = 0

  $x^{2} -(\frac{-8}{3} )x+(\frac{4}{3} )=0 \\\\ x^{2} +\frac{8}{3} x + \frac{4}{3} =0\\\\ \frac{3x^{2} +8x+4}{3}=0 \\\\ 3x^{2} +8x+4=0\times3\\\\ 3x^{2} +8x+4=0$

=> The quadratic polynomial is 3x²+8x+4