Question

find the quadratic polynomial whose sum and product of the zeroes are 3 and 9/4?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer :

$4 {x}^{2} - 12x + 9 = 0$

Given that :

The sum of the zeroes of Polynomial = 3 and

The product of the zeroes of the Polynomial = 9/4

As we know that :

The equation of quadratic polynomial :

${x}^{2} - (sum \: of \: zeroes)x + (product \: of \: zeroes) \\ \\ = > {x}^{2} - 3x + \frac{9}{4} = 0 \\ \\ = > \frac{(4 {x}^{2} - 12x + 9)}{4} = 0 \\ \\ = > 4 {x}^{2} - 12x + 9 = 0$

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