Question

find the quadratic polynomial whose sum and product of zeros are 9 and 1/9​

Answer 1

Answer:

Zeroes=9,1/9

Sum of zeroes=9+1/9

=81+1/9

=82/9

Product of zeroes = 9x 1/9=1

Quadratic polynomial = x^2 -(sum of zeroes)x + product of zeroes

=x^2 -82/9x+1

=9x^2 -82x +9

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Answer 2

Step-by-step explanation:

$k( {x}^{2} -s x + p)$

$k( {x}^{2} - 9x + \frac{1}{9} )$

$9( {x}^{2} - 9x + \frac{1}{9} )$

$9 {x}^{2} - 81x + 1$

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