Find the quadratic polynomial whose sum and product zeroes are -8/3,4/3
Answers
Answered by
1
Step-by-step explanation:
Answer:
3x² - 4x + 9 = 0
Step-by-step explanation:
We know that every Quadratic Equation is of form
k [ x² - ( sum of roots) x + (product of roots)], where k is any constant value
Now sum of roots = -4/3 and product of roots = 3
∴ Desired equation will be
k[ x² - (-4/3)x + 3] = 0
Let k = 3 [ LCM of denominators is 3]
3[x² - (4/3)x +3] = 0
3x² - 4x + 9 = 0
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Answered by
2
Answer:
Step-by-step explanation:
Sum of zeroes =-8/3
Product of zero =4/3
Quadratic equation:
x^2 +8/3x + 4/3
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