Question

Find the quadratic polynomial whose sum of zeroes is 8, and product of zeroes is 12. Hence find the zeroes

Answer 1

=k(x²-(α+β)x+αβ)

=k(x²-8x+12)

here k=1

=x²-8x+12

=x²-2x-6x+12

=x(x-2)-6(x-2)

=(x-2)(x-6)

⇒x-2=0                                    or                        ⇒x-6=0

⇒x=2                                        or                            ⇒x=6

Answer 2

Answer:

I hope this answer helps you.......