Find the quadratic Polynomial whose sum of zeroes is 9
and Product is 18. Hence find the zeroes of the Polynomial
Answers
Answered by
1
Answer:
your answer here friend
Step-by-step explanation:
Given: Sum for zeroes = (α+β)=8
Product of the zeroes = αβ=12
Required quadratic polynomial is
x
2
−(α+β)x+αβ=x
2
−(8)x+12
Now , find the zeroes of the above polynomial.
Let f(x)=x
2
−(8)x+12
= x
2
−6x−2x+12
=(x−6)(x−2)
Substitute f(x)=0
(x−6)=0 or (x−2)=0
⇒x=6 or x=2
2 and 6 are the zeroes of the polynomial .
Answered by
1
We know:
- P()={-(a+b)+a+b}
Sum(a+b)=9
product(ab)=18
Now Putting the values,
{-(9)+18}
-9+18
+6-3+18
(+6) - 3(+6)
(+6)(-3)
Hence,
=> +6=0
=> = -6
=>. -3=0
=> = 3
therefore,
- -6 and 3 are the zerose's of the given polynomial.
Similar questions
Math,
22 days ago
English,
22 days ago
Social Sciences,
22 days ago
English,
1 month ago
Social Sciences,
1 month ago
Business Studies,
9 months ago
Science,
9 months ago
Math,
9 months ago