Math, asked by shivam9821, 9 months ago

find the quadratic polynomial whose sum of zeros is √2 and product of zeroes is 1/3.
please solve it fast........

Answers

Answered by Asanhmr
1

Answer: One of solution is

3x^2 - 3√2x +1

There may be many solutions...

Step-by-step explanation:

Formula , S= sum of zeroes, P= product of zeroes, then

x^2 - Sx +P,

S=√2, P=1/3

x^2 - √2x +1/3

= (3x^2 - 3√2x +1) /3

= 1/3(3x^2 - 3√2x +1)

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